[straube]

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT

South is captain. Let's say North shows pattern and 8 QPs at 4C. A good one for reverse relays no doubt.

1) With rules of short to long (and stop with odd for singleton or doubleton), king parity last

4D-4N even heart, odd club, even spade (KQT8 J8 A62x K93 still possible)
5C-5S odd diamond, DK
Cards placed

2) With rules of short to long (and stop with odd for singleton or doubleton), king parity first

4D-5C even kings, even heart, odd club
5D-5H even spade (KQT8 J8 Axxx K93 still possible)
5S-6C odd diamond (KQT8 J8 Axxx K93 still possible)


3) With rules of long to short (and stop for singleton only), K parity last

4D-4H even spade
4S-5N odd diamond, odd club, even heart (rule change), DK
Cards placed

4) With rules of long to short (and stop for singleton only), K parity first

4D-4S even K, even spade
4N-5S odd diamond, odd club, even heart (rule change) (KQT8 J8 A862 K93 still possible)

[foobar]

straube, on 2017-October-19, 21:18, said:

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT

4D....4H (relay; even K parity...could be S(AKQ)...K(D|C) among others)
4S....4N (relay; nothing in hearts; even spade...S(AKQ) is out the window. S(KQ)...D(A)...C(K) or the above?

Can relay, but won't be resolved:

5C....5S (relay; odds in ♦+[♣)

[awm]

Several things about this hand: 1. We would reverse relay 2. If we can't reverse relay, we would use a shortness-showing sequence.

Ignoring all of that:

4♦ - 4♥ (even spades)
4♠ - 5♦ (odd diamonds, odd clubs, even hearts).

At this point it's either:

♠AQ + ♦K + ♣K
♠KQ + ♦A + ♣K

But it does not really matter. Partner's heart jack is not something we can find out for sure, so I'd just blast six in either case. I suppose we can resolve via:

5♥ - 5NT (on the actual hand, we pair ♠+♦ since one has king and other other queen, and we show that lower suit has the king; on the other option we would pair ♠+♥ since one has KQ and the other neither honor, and bid 5♠ since higher suit has king).

[yunling]

4♦-4♠(ask 1&2, 0/3/6)
the ask is not effective with shortage in suit 1, but a next move is okay here since if partner is 1/4 in suit 2&3 5H signoff is still possible.

4NT-5NT(ask 2&3, 2/5 no honor in H even Kings)
♠KQ ♦A ♣K is still possible but won't matter

[sieong]

EPCB.
4♦ - 4♥ (even ♠)
4♠ - 5♥ (even ♥ odd ♦ odd ♣)

At this point this converges to classic PCB, but one step worse.

[nullve]

straube, on 2017-October-19, 21:18, said:

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT

Auction, with some ambiguity left out:

(...)
4♣-4♦ (11-13 hcp (say); relay)
4♥-4♠ (even # of kings; relay)
5♣-5♦ (odd # of queens, no ♠K; relay)
6♣-? (♦K, ♣K, ♠Q, no ♠J).

So Teller could still have Qxxx xxx AKxx Kxx.

This post has been edited by nullve: 2017-November-02, 08:07