polish club beginner
#1
Posted 2014-April-10, 02:33
1♣-1♦
2♣-?
At this moment, we know:
Opener: 5+♣, 15-22 (anything below a GF+), no 4-card major. 2♣ is non-forcing
Responder: 0-6 any/7-11 unbalanced without a 4-card M (one or both minors, unbalanced)/13+balanced
Jassem's ebook does not cover it. Is there anything simple with as few artificial bids as possible? I would like to play a 1C structure that I can write down in 1 or 2 pages, so this sequence has maybe 1 line or 2 as its fair share. This seems like an uncommon sequence, what with all the passes from opps.
I'm thinking something like:
2♦-GF artificial. handles good minor-oriented hands that are now GF+balanced hands
2♥/2♠-stop or natural?
3♣ should be NF but what about 2NT?
George Carlin
#2
Posted 2014-April-10, 04:47
-- Bertrand Russell
#3
Posted 2014-April-10, 06:03
George Carlin
#4
Posted 2014-April-10, 06:30
gwnn, on 2014-April-10, 06:03, said:
Of course it depends how you play the 1NT and 2NT responses to 1♣
Jassem suggests 1♣-1NT as 8-11 and changed his mind what 2NT shows, but stronger of course than a 1NT response.
Therefor
1♣-1♦
2♣-2NT would show 6-7 balanced.
I like to play that 1♣-1NT is invitational opposite a weak notrump, so I could be as strong as a poor ten for bidding 1♦ and still be balanced.
But with 9-10 I would force opposite a 2♣ rebid by opener. So 2NT shows less.
A simple approach is to play something analogous what you play over a precision 2♣ opening.
2♦ is forcing but not necessarily game forcing and with the difference that a bid in a yet unbid major by responder after 2♦ shows a stopper not a suit, because with a major suit responder can not be strong enough to bid 2♦ first.
Rainer Herrmann
#5
Posted 2014-April-10, 07:56
rhm, on 2014-April-10, 06:30, said:
2♦ is forcing but not necessarily game forcing and with the difference that a bid in a yet unbid major by responder after 2♦ shows a stopper not a suit, because with a major suit responder can not be strong enough to bid 2♦ first.
Would opener's 2M rebids then show 3-card suits?
George Carlin
#6
Posted 2014-April-10, 09:38
1C--1D; 2C---
P = Too weak to act
2D = Multi, weak major or 16+ balanced
2H = 4+ clubs, 7--11
2S = 6+ diamonds, 7--11
2N = 13--15 balanced
3C = About 4--6 with some club support
Two line summary:
Responder bids 2M Lissabon style with 7--11 unbalanced (clubs has priority). 2NT shows 13--15 bal.
A weak responder can pass, raise clubs or bid 2D multi, showing either a weak major or 16+ bal.
#7
Posted 2014-April-10, 16:06
gwnn, on 2014-April-10, 06:03, said:
INV with the type that is trying to find out whether we have 25 HCP combined. I think checking for stoppers when we have 25 HCP is overrated (they might not find the lead, they might break 4-4, they might block...) but I seem to recall that we've disagreed on this already in the past.
-- Bertrand Russell
#8
Posted 2014-April-11, 04:45
mgoetze, on 2014-April-10, 16:06, said:
Could you be a bit more specific? I know what invitational means. Partner can have 15-22, as mentioned. So we can have 25 HCP together with 3-9 HCP (with 10 we know we have it already). So do you mean 3-6 balanced? Or can it also have something like Kxx x QJxxxx xxx? Is this a hand in which you are not worried about a heart stop at all?
George Carlin
#10
Posted 2014-April-11, 13:17
gwnn, on 2014-April-11, 04:45, said:
3-6 is too large, partner won't know what to do, and I don't want to stop in 2NT on a combined 18-count either. My thought was 5-6 but I would want to run a sim to find out the frequency of responder's various hand types in this situation before deciding. And yes, the given hand is one where I wouldn't want to worry too much about a heart stop. (BTW both opponents have had at least one chance to bid 1♥.)
-- Bertrand Russell
#11
Posted 2014-April-11, 14:00
How about?
2D-a 6-cd major, 0-5
.....paradoxical advances
2H-5+D,7-11, 1-suited
.....2S-GF, relays for shape
.....2N-requests 3C for p/c
.....3C-inv
.....3D-inv
2S-4+ clubs, 7-11
.....2N-GI, f
2N-0-4 club raise
3C-5-6 club raise
etc-bal 13+ in steps?
I really don't like taking up so much room with the balanced 13+ but you have a lot of weaker hands to sort out.
#12
Posted 2014-April-11, 20:34
#13
Posted 2014-April-12, 02:15
antonylee, on 2014-April-11, 20:34, said:
3♣ should be a 6-card suit but maybe you can sell some of those 5-carders as balanced hands or bid 3♣ anyway, or open an overstrength 1♦ on 5-4. What were your continuations over 2C?
George Carlin
#14
Posted 2014-April-12, 03:40
gwnn, on 2014-April-10, 07:56, said:
This assumes that opener will rarely bypass a 4 card major when bidding 2♣, which is reasonable and in the Polish tradition (Mafia). This looks to me a simple but good approach.
If 1♣-1♦-3♣ shows a six card suit and a hand just short of forcing to game, it is important to understand that 1♣-1♦-2♣ must cover some strong, but difficult to describe unbalanced distributions and could be based on as little as 4 clubs when 18+ with longer diamonds.
Over 1♣-1♦-2♣ 2M by responder shows a weak hand and is not encouraging while 2♦ is the only force.
Opener bids a 3 card major only if opener has shortage or no half stopper in the other major, since responder can not have a 4 card major and enough to rebid a forcing 2♦.
For example if you hold something like ♠Ax ♥x ♦AJxxxx ♣AKQx I would probably rebid 2♣ hoping to follow up with 3♦ (diamonds at least as long as clubs).
If you hold (13)-5♦-4♣ 18+ you rebid 2♣ and if partner bids 2♦ you bid your 3 card major followed by 3♦ if possible.
Not ideal, but I do not see anything better.
Rainer Herrmann
#15
Posted 2014-April-14, 03:05
gwnn, on 2014-April-12, 02:15, said:
Yes, strong hands with 5♣ were either treated as 6-carders or balanced hands.
Otherwise close to what Rainer suggests: 2M=weak, 2♦=art. F, 2N~7-8 bal.
I don't think we really ever discussed the non-weak options as they are exceedingly rare anyways but I guess a better (although still very simple) structure could be:
2♦=Staymanish signoff, or 13+; 2M=weak 5(6)M; 2N=7-8 bal with 2♣; 3♣ 7-8, fit; 3♦=nat, 7-11; higher=♣, 7-11.