[jillybean]

---

We were one of four pairs, out of 18, who bid it. It's hard to argue with results but I don't know how we could bid it intelligently.

Playing 12-14 nt , I open 1♦

1♦ 2♣ (clubs, gf)
3♣ 3♦
3♥ 4♦*
5♣ 2+Q ....

[eagles123]

1N - 3S (Splinter)

4D - 4N (Keycard)

5D (3) - 5H (Q?)

5N Q+no KS or KC - 6C (Qc?)

7D (yes) - 7N (Can count 13)

[mw64ahw]

I can concoct a reply using 4-way transfers, but with a known (by North) 34/35 points between you the following is all that is required after South's response

1NT-4♣ (Super Gerber version)
4NT (2 Aces & 1 King)-7NT

[Cyberyeti]

Converting our NT system to strong NT.

1N-2♠(weak one minor or GF SI both minors at least 5-4)
3♣(4+♦)-3♥(both minors cue agrees ♦)
3♠(cue)-4♣(cue)
4♦-4♥(aces ?)
4♠(0/3)-4N(Q?)
5N(yes, no side kings but extras)-6♣(I have one of the K/Q, bid the grand with the other)
7♦-7N

[gszes]

after a 1n opening 15-17 we are going to be in at least 6n so how do we search for 7? IMHO
1n 15-17
2s Minor Suit Stayman (MSS) (0 to unlimited)
3d 4+ diamonds denies 4+ clubs
4c RKC for diamonds (you can use CRO here as well)
5d 0 or 3
5h specific king ask (yes even knowing p has no extra kings because it can get us info on club Q yay or nay)
5n no kings but a useful Q (clubs Q is useful because of the MSS bid)
7n can count 4c 4d 3h 2s as a minimum

[LBengtsson]

I bid it easy but will find ♣4-1/5-0 and ♦4-0 in opposite hands

[Winstonm]

LBengtsson, on 2021-April-14, 08:45, said:

I bid it easy but will find ♣4-1/5-0 and ♦4-0 in opposite hands

Well, if both are guarded by the same hand you can find a simple squeeze by playing off the majors winners first.

[Cyberyeti]

Winstonm, on 2021-April-14, 09:03, said:

Well, if both are guarded by the same hand you can find a simple squeeze by playing off the majors winners first.

Actually if E has the 4 diamonds you can pick them up, so it's only an issue if W has 4 diamonds and E 5 clubs.

[Winstonm]

Cyberyeti, on 2021-April-14, 10:46, said:

Actually if E has the 4 diamonds you can pick them up, so it's only an issue if W has 4 diamonds and E 5 clubs.

And if such is the case, the bridge god must really hate you.

[Cyberyeti]

Winstonm, on 2021-April-14, 10:56, said:

And if such is the case, the bridge god must really hate you.

Oh they do, 2 recent examples, we bid a grand that demanded 2 suits only missing the J were Jxxx offside and they were. Also were originally cost a swiss teams event by investigating a slam, signing off in 5 and getting the 5-0 offside break required to beat it. Then when they stuck the results up on the net we found a score entered the wrong way to win by a VP.

[apollo1201]

Cyberyeti, on 2021-April-14, 11:09, said:

Oh they do, 2 recent examples, we bid a grand that demanded 2 suits only missing the J were Jxxx offside and they were. Also were originally cost a swiss teams event by investigating a slam, signing off in 5 and getting the 5-0 offside break required to beat it. Then when they stuck the results up on the net we found a score entered the wrong way to win by a VP.

I was thinking when you went down in 5, the other table peacefully played in 3 making 10 tricks. Or had left your teammates defend in 4 something for 1 or 2 NV undoubled tricks. Same for the grand, they would be playing 4 making 11 on a sloppy play🤣🤣.