pran, on 2015-August-20, 01:10, said:
In that case he would (as the cards lie) end up with 9 tricks only.
WellSpyder, on 2015-August-20, 02:31, said:
Exactly - so are you ruling down 1?
billw55, on 2015-August-20, 06:13, said:
That would be wrong IMO, and I do not think pran meant that. Even a careless declarer (which this one was) cannot fail to notice north showing out on the first round of trump. It doesn't even matter which trump is played from dummy.
I suppose one could contrive to come up with 9 tricks - perhaps ruling that declarer miscounted his own trumps, thinking he had seven. (We know the ten looks like two right?
) But I think this would be too harsh.
I think (and would rule correspondingly) that a reasonable line of play is: Win the lead with the
♠Q and draw a high trump from East.
Now cross to dummy with a second trump and run the spades until South trumps, win the return from South, cross to Dummy with his last trump (pulling the last trump from South) and run the remaining spades.
This line only requires Declarer to recognize that South had all four outstanding trumps so that he must be forced to use one of them on a spade while Dummy still has a high trump for a final entry.
Not too demanding.